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Thursday, November 12, 2009

Posted by venu k
3 comments | 1:17 AM

Method 1:


#!/bin/bash
#
# SCRIPT : leapyear.sh
# PURPOSE: Checks whether given year is a leap year or not
# USAGE : sh leapyear.sh
# If Year value not supplied, it takes current year as default
#
# This script based on, One year has the length of 365 days, 5 hours,
# 48 minutes and 47 seconds. Because this is rather non-functional,
# a normal year has been given 365 days and a leap year 366 days.

#####################################################
############### DEFINE FUNCTIONS HERE ####################
#####################################################

Leap()
{

# This function tells you if the argument is a leap year or not...

YEAR=$1
NO_OF_DAYS=$(cal $YEAR |egrep "^[ 0-9][0-9]| [ 0-9][0-9]$" |wc -w)


# A single parameter to cal specifies the year (1 - 9999) to be displayed;
# note the year must be fully specified: “cal 89” will not display a calendar
# for 1989.

# Use egrep or grep -E both are same

# cal command pipes total months and dates to egrep, egrep remove all lines
# not starting with number or ending with number, then pipes remaining lines
# to wc command. wc command counts total number of words(days).

if [[ $NO_OF_DAYS -eq 365 ]]
then
echo "$YEAR Is Not A Leap Year "
else
echo "$YEAR Is A Leap Year"
fi

}

#####################################################
############### MAIN PROGRAM STARTS HERE #################
#####################################################

Year=${1:-$(date +%Y)}
if [ $Year -lt 1 -o $Year -gt 9999 ]
then
echo "Illegal Year Value: Use 1-9999"
exit 1
fi

Leap $Year

Method 2:


#!/bin/bash
#
# SCRIPT : leapyear.sh
# PURPOSE: Checks whether given year is a leap year or not
# USAGE : sh leapyear.sh
# If Year value not supplied, it takes current year as default
#
# This script based on,A leap year comes every 4 years,
# but not every 100 years, then again every 400 years.


#####################################################
############### ARGUMENTS CHECKING #####################
#####################################################

YEAR=${1:-`date +%Y`}

if [ $YEAR -lt 1 -o $YEAR -gt 9999 ]
then
echo "Illegal Year Value: Use 1-9999"
exit 1
fi

#####################################################
############### DECLARE VARIABLES HERE ###################
#####################################################

rem1=$((YEAR%4))
rem2=$((YEAR%100))
rem3=$((YEAR%400))

#####################################################
############## MAIN PROGRAM STARTS HERE ##################
#####################################################

if [ ${rem3} = "0" ]
then
echo "$YEAR Is A Leap Year"
exit
fi

if [ ${rem2} = "0" -a ${rem3} != "0" ]
then
echo "$YEAR Is Not A Leap Year"
exit
fi

if [ ${rem1} = "0" -a ${rem2} != "0" ]
then
echo "$YEAR Is A Leap Year"
else
echo "$YEAR Is Not A Leap Year"
fi

OUTPUT:

[root@localhost shell]# ./leapyear.sh
2009 Is Not A Leap Year
[root@localhost shell]# ./leapyear.sh 2100
2100 Is Not A Leap Year
[root@localhost shell]# ./leapyear.sh 2104
2104 Is A Leap Year
[root@localhost shell]# ./leapyear.sh 21000
Illegal Year Value: Use 1-9999
[root@localhost shell]# ./leapyear.sh 1996
1996 Is A Leap Year

3 comments:

  1. nice work!
    i really very impress with ur way to explain.

    ReplyDelete
  2. is_leap_year() { ## USAGE: is_leap_year [year]
    ily_year=${1:-`date +%Y`}
    case $ily_year in
    *0[48] |\
    *[2468][048] |\
    *[13579][26] |\
    *[02468][048]00 |\
    *[13579][26]00 ) _IS_LEAP_YEAR=1
    return 0 ;;
    *) _IS_LEAP_YEAR=0
    return 1 ;;
    esac
    }

    ReplyDelete
  3. Print a reverse the number

    echo "Enter a number"
    read n
    sd=0
    rev=0

    while [ $n -gt 0 ]
    do
    sd=$(( $n % 10 ))
    rev=$(( $rev *\ 10 + $sd ))
    n=$(( $n / 10 ))
    done

    echo "Reverse number of entered digit is $rev"

    $ vi fibonacci.sh echo “Enter n for Fibonacci series: - “
    read n
    echo “Fibonacci series is: - “
    echo “0”
    echo “1”
    i=0
    j=1
    cnt=2
    while [ $cnt –le $n ]
    do
    k=`expr $i + $j`
    i= $j
    j= $k
    echo $k
    cnt=`expr $cnt + 1`
    done
    Run the above script as follows: $ /bin/sh fibonacci.sh

    Code:
    Output –
    Enter n for Fibonacci Series:-
    10
    Fibonacci Series is:-
    0
    1
    1
    2
    3
    5
    8

    clear
    echo "How many number of terms to be generated ?"
    read n
    x=0
    y=1
    i=2
    echo "Fibonacci Series up to $n terms :"
    echo "$x"
    echo "$y"
    while [ $i -lt $n ]
    do
    i=`expr $i + 1 `
    z=`expr $x + $y `
    echo "$z"
    x=$y
    y=$z
    done

    Write a shell program in unix to add two numbers?

    #!/bin/sh
    echo “Enter the number”
    A=5
    B=10
    C=`echo "$A + $B"|bc -l`
    echo "$A + $B = $C"
    Or
    echo "enter the value of a"
    read a
    echo "enter the value of b"
    read b
    c=`expr $a + $b`
    echo "the sum of a and b is $c"
    shell script for check whether the given no is prime or not??
    echo "input any number:"
    read no
    no=`expr $no`
    i=`expr 2`
    while [ $i -lt $no ]
    do
    if [ `expr $no % $i` -eq 0];
    then
    echo "$no is not a prime no.."
    break 2
    fi
    i=`expr $i +1`
    done

    if [ $i -eq $no ];
    then
    echo "$no is a PRIME no..."
    fi
    factorial of a number in Unix

    echo "Total no of factorial wants"
    read fact

    ans=1
    counter=0
    while [ $fact -ne $counter ]
    do
    counter=`expr $counter + 1`
    ans=`expr $ans \* $counter`
    done
    echo "Total of factorial is $ans"

    -------------------------------------------------------------------
    output
    -------------------------------------------------------------------
    Total no of factorial wants
    5
    Total of factorial is 120
    Or
    clear
    i=1
    f=1
    echo "Enter the n value:"
    read n
    while [ $i -le $n ]
    do
    f=`expr $f \* $i`
    i=`expr $i + 1`
    done
    echo "The factorial of $n is":$f
    /*-------------------------INPUT/OUTPUT----------
    Enter the n value:
    6
    The factorial of 6 is:720

    ReplyDelete